**Strings Making Anagrams**: Looking for “Strings Making Anagrams” solution for Hackerrank problem? Get solution with source code and detailed explainer video.

A student is taking a cryptography class and has found anagrams to be very useful. Two strings are anagrams of each other if the first string’s letters can be rearranged to form the second string. In other words, both strings must contain the same exact letters in the same exact frequency. For example, * bacdc* and

*are anagrams, but*

**dcbac***and*

**bacdc***are not.*

**dcbad**The student decides on an encryption scheme that involves two large strings. The encryption is dependent on the minimum number of character deletions required to make the two strings anagrams. Determine this number.

Given two strings,

**a**and

**b,**that may or may not be of the same length, determine the minimum number of character deletions required to make

**a**and

**b**anagrams. Any characters can be deleted from either of the strings.

Go to problem statement

## Explanation Video:

Youtube Channel partner: CodingCart

Mentor: Satyendra Jaiswal

Langauge: Python

## Source Code: for `makeAnagram`

function

```
# Complete the makeAnagram function below.
def makeAnagram(a, b):
c1=Counter(a)
for c in b:
c1[c]-=1
val=c1.values()
s=sum(abs(i) for i in val)
return s
```

## Full Source Code:

```
#!/bin/python3
import math
import os
import random
import re
import sys
from collections import Counter
# Complete the makeAnagram function below.
def makeAnagram(a, b):
c1=Counter(a)
for c in b:
c1[c]-=1
val=c1.values()
s=sum(abs(i) for i in val)
return s
if __name__ == '__main__':
fptr = open(os.environ['OUTPUT_PATH'], 'w')
a = input()
b = input()
res = makeAnagram(a, b)
fptr.write(str(res) + '\n')
fptr.close()
```

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