jumpingOnClouds HackerRank Solution:Looking for jumpingOnClouds solution for Hackerrank problem? Get solution with source code and detailed explainer video
There is a new mobile game that starts with consecutively numbered clouds. Some of the clouds are thunderheads and others are cumulus. The player can jump on any cumulus cloud having a number that is equal to the number of the current cloud plus 1 or 2. The player must avoid the thunderheads. Determine the minimum number of jumps it will take to jump from the starting postion to the last cloud. It is always possible to win the game.
For each game, you will get an array of clouds numbered 0 if they are safe or 1 if they must be avoided.
Go to problem statement
Youtube Channel partner: CodingCart
Mentor: Satyendra Jaiswal
Source Code: for
# Complete the jumpingOnClouds function below. def jumpingOnClouds(c): count=0 i=0 while i< len(c)-1: #for 2 jumps if i+2<len(c) and c[i+2]==0: i+=1 i+=1 count+=1 return count
Full Source Code:
#!/bin/python3 import math import os import random import re import sys # Complete the jumpingOnClouds function below. def jumpingOnClouds(c): count=0 i=0 while i< len(c)-1: #for 2 jumps if i+2<len(c) and c[i+2]==0: i+=1 i+=1 count+=1 return count if __name__ == '__main__': fptr = open(os.environ['OUTPUT_PATH'], 'w') n = int(input()) c = list(map(int, input().rstrip().split())) result = jumpingOnClouds(c) fptr.write(str(result) + '\n') fptr.close()
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